y^2-3y+40=0

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Solution for y^2-3y+40=0 equation:


Simplifying
y2 + -3y + 40 = 0

Reorder the terms:
40 + -3y + y2 = 0

Solving
40 + -3y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -3y + -40 + y2 = 0 + -40

Reorder the terms:
40 + -40 + -3y + y2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -3y + y2 = 0 + -40
-3y + y2 = 0 + -40

Combine like terms: 0 + -40 = -40
-3y + y2 = -40

The y term is -3y.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3y + 2.25 + y2 = -40 + 2.25

Reorder the terms:
2.25 + -3y + y2 = -40 + 2.25

Combine like terms: -40 + 2.25 = -37.75
2.25 + -3y + y2 = -37.75

Factor a perfect square on the left side:
(y + -1.5)(y + -1.5) = -37.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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